t^(2/3)+t^(1/3)-16

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Solution for t^(2/3)+t^(1/3)-16 equation: 


t in (-oo:+oo)

t^(2/3)+t^(1/3)-16 = 0

t_1 = t^(1/3)

1*t_1^2+1*t_1^1-16 = 0

t_1^2+t_1-16 = 0

DELTA = 1^2-(-16*1*4)

DELTA = 65

DELTA > 0

t_1 = (65^(1/2)-1)/(1*2) or t_1 = (-65^(1/2)-1)/(1*2)

t_1 = (65^(1/2)-1)/2 or t_1 = (-(65^(1/2)+1))/2

t_1 = (-(65^(1/2)+1))/2

t^(1/3)-((-(65^(1/2)+1))/2) = 0

t^(1/3)+(1/2)*(65^(1/2)+1) = 0

1*t^(1/3) = -(1/2*(65^(1/2)+1)) // : 1

t^(1/3) = -1/2*(65^(1/2)+1)

( -1/2*(65^(1/2)+1) < 0 i 1/3 in (0:1) ) => t naleu017Cy do O

t_1 = (65^(1/2)-1)/2

t^(1/3)-((65^(1/2)-1)/2) = 0

1*t^(1/3) = (65^(1/2)-1)/2 // : 1

t^(1/3) = (65^(1/2)-1)/2

t^(1/3) = (65^(1/2)-1)/2 // ^ 3

t = ((65^(1/2)-1)^3)/8

t = ((65^(1/2)-1)^3)/8

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